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题目描述

给两个数\(a\)与\(b\)，执行以下操作：
定义两个变量\(sum\)和\(carry\)
使\(sum\)等于\(a\)异或\(b\)
使\(carry\)等于\(a\)与\(b\)后左移一位
使\(a\)等于\(sum\)
使\(b\)等于\(carry\)
重复2~5步直到\(b\)等于\(0\)
输出\(a\)

格式

输入

Two integers x and y, satisfying 0 <= x, y <= 32767.

输出

One integer, the sum of x and y.

样例

输入

123 500

输出

623

数据约束

1s, 1024KiB for each test case.

提示

Free Pascal Code

var a,b:longint;
begin
    readln(a,b);
    writeln(a+b);
end.

C Code

#include <stdio.h>
int main(void)
{
    int a, b;
    scanf("%d%d", &a, &b);
    printf("%d\n", a + b);
    return 0;
}

C++ Code

#include <iostream>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    return 0;
}

Python Code

a, b = [int(i) for i in raw_input().split()]
print(a + b)

Java Code

import java.io.*;
import java.util.Scanner;

public class Main {

    /**
     * @param args
     * @throws IOException 
     */
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        System.out.println(a + b);
    }
}